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11401140113 = 112933537431
BaseRepresentation
bin10101001111000111…
…11001011110010001
31002102120020221000122
422213203321132101
5141322142440423
65123154000025
7552350043356
oct124743713621
932376227018
1011401140113
114920712350
122262276015
1310c9077b6c
147a229062d
1546adca8c8
hex2a78f9791

11401140113 has 8 divisors (see below), whose sum is σ = 12480060096. Its totient is φ = 10329295600.

The previous prime is 11401140071. The next prime is 11401140187. The reversal of 11401140113 is 31104110411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11401140113 - 232 = 7106172817 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11401140091 and 11401140100.

It is not an unprimeable number, because it can be changed into a prime (11401140193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1765493 + ... + 1771938.

It is an arithmetic number, because the mean of its divisors is an integer number (1560007512).

Almost surely, 211401140113 is an apocalyptic number.

It is an amenable number.

11401140113 is a deficient number, since it is larger than the sum of its proper divisors (1078919983).

11401140113 is a wasteful number, since it uses less digits than its factorization.

11401140113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3537735.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 11401140113 its reverse (31104110411), we get a palindrome (42505250524).

The spelling of 11401140113 in words is "eleven billion, four hundred one million, one hundred forty thousand, one hundred thirteen".

Divisors: 1 11 293 3223 3537431 38911741 1036467283 11401140113