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114011440143 = 390434202567
BaseRepresentation
bin110101000101110011…
…1001000010000001111
3101220021122122020202020
41222023213020100033
53331443412041033
6124213124501223
711144211152136
oct1521347102017
9356248566666
10114011440143
11443965384a7
121a11a24a813
13a99c5c5823
145737c7491d
152e7437c6b3
hex1a8b9c840f

114011440143 has 8 divisors (see below), whose sum is σ = 152032099968. Its totient is φ = 75999203544.

The previous prime is 114011440129. The next prime is 114011440157. The reversal of 114011440143 is 341044110411.

It is an interprime number because it is at equal distance from previous prime (114011440129) and next prime (114011440157).

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 114011440143 - 25 = 114011440111 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114011440643) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2074155 + ... + 2128412.

It is an arithmetic number, because the mean of its divisors is an integer number (19004012496).

Almost surely, 2114011440143 is an apocalyptic number.

114011440143 is a deficient number, since it is larger than the sum of its proper divisors (38020659825).

114011440143 is an equidigital number, since it uses as much as digits as its factorization.

114011440143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4211613.

The product of its (nonzero) digits is 768, while the sum is 24.

Adding to 114011440143 its reverse (341044110411), we get a palindrome (455055550554).

The spelling of 114011440143 in words is "one hundred fourteen billion, eleven million, four hundred forty thousand, one hundred forty-three".

Divisors: 1 3 9043 27129 4202567 12607701 38003813381 114011440143