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1140123434343 = 3380041144781
BaseRepresentation
bin10000100101110100101…
…001101111110101100111
311000222212011101102022120
4100211310221233311213
5122134433044344333
62231433202001023
7145241215202145
oct20456451576547
94028764342276
101140123434343
113aa583a57093
12164b69046173
13836895b79ba
143d27a206595
151e9cd21adb3
hex10974a6fd67

1140123434343 has 4 divisors (see below), whose sum is σ = 1520164579128. Its totient is φ = 760082289560.

The previous prime is 1140123434299. The next prime is 1140123434377. The reversal of 1140123434343 is 3434343210411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1140123434343 - 226 = 1140056325479 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1140123434143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 190020572388 + ... + 190020572393.

It is an arithmetic number, because the mean of its divisors is an integer number (380041144782).

Almost surely, 21140123434343 is an apocalyptic number.

1140123434343 is a deficient number, since it is larger than the sum of its proper divisors (380041144785).

1140123434343 is an equidigital number, since it uses as much as digits as its factorization.

1140123434343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 380041144784.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 1140123434343 its reverse (3434343210411), we get a palindrome (4574466644754).

The spelling of 1140123434343 in words is "one trillion, one hundred forty billion, one hundred twenty-three million, four hundred thirty-four thousand, three hundred forty-three".

Divisors: 1 3 380041144781 1140123434343