Base | Representation |
---|---|
bin | 10000100101110100101… |
… | …001101111110101100111 |
3 | 11000222212011101102022120 |
4 | 100211310221233311213 |
5 | 122134433044344333 |
6 | 2231433202001023 |
7 | 145241215202145 |
oct | 20456451576547 |
9 | 4028764342276 |
10 | 1140123434343 |
11 | 3aa583a57093 |
12 | 164b69046173 |
13 | 836895b79ba |
14 | 3d27a206595 |
15 | 1e9cd21adb3 |
hex | 10974a6fd67 |
1140123434343 has 4 divisors (see below), whose sum is σ = 1520164579128. Its totient is φ = 760082289560.
The previous prime is 1140123434299. The next prime is 1140123434377. The reversal of 1140123434343 is 3434343210411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1140123434343 - 226 = 1140056325479 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1140123434143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 190020572388 + ... + 190020572393.
It is an arithmetic number, because the mean of its divisors is an integer number (380041144782).
Almost surely, 21140123434343 is an apocalyptic number.
1140123434343 is a deficient number, since it is larger than the sum of its proper divisors (380041144785).
1140123434343 is an equidigital number, since it uses as much as digits as its factorization.
1140123434343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 380041144784.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 1140123434343 its reverse (3434343210411), we get a palindrome (4574466644754).
The spelling of 1140123434343 in words is "one trillion, one hundred forty billion, one hundred twenty-three million, four hundred thirty-four thousand, three hundred forty-three".
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