Base | Representation |
---|---|
bin | 11001111011000110011100… |
… | …100011111100101000011011 |
3 | 112221200111021111022100121101 |
4 | 121323012130203330220123 |
5 | 104420440132041311103 |
6 | 1042252345043052231 |
7 | 33005063603052010 |
oct | 3173063443745033 |
9 | 487614244270541 |
10 | 114012533541403 |
11 | 33367497979a42 |
12 | 10954486971077 |
13 | 4b8044992b683 |
14 | 2022343aa5707 |
15 | d2aadabcea1d |
hex | 67b19c8fca1b |
114012533541403 has 8 divisors (see below), whose sum is σ = 130329273288672. Its totient is φ = 97703102533056.
The previous prime is 114012533541293. The next prime is 114012533541503. The reversal of 114012533541403 is 304145335210411.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 114012533541403 - 217 = 114012533410331 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114012533541503) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1827151300 + ... + 1827213697.
It is an arithmetic number, because the mean of its divisors is an integer number (16291159161084).
Almost surely, 2114012533541403 is an apocalyptic number.
114012533541403 is a deficient number, since it is larger than the sum of its proper divisors (16316739747269).
114012533541403 is an equidigital number, since it uses as much as digits as its factorization.
114012533541403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3654369461.
The product of its (nonzero) digits is 86400, while the sum is 37.
Adding to 114012533541403 its reverse (304145335210411), we get a palindrome (418157868751814).
The spelling of 114012533541403 in words is "one hundred fourteen trillion, twelve billion, five hundred thirty-three million, five hundred forty-one thousand, four hundred three".
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