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114013000423 = 727929453113
BaseRepresentation
bin110101000101110110…
…1000101001011100111
3101220021202120112001101
41222023231011023213
53331444312003143
6124213222140531
711144230341100
oct1521355051347
9356252515041
10114013000423
1144397403793
121a11a881747
13a99ca20a7a
14573815d3a7
152e74589b4d
hex1a8bb452e7

114013000423 has 12 divisors (see below), whose sum is σ = 134306199840. Its totient is φ = 96488394912.

The previous prime is 114013000399. The next prime is 114013000457. The reversal of 114013000423 is 324000310411.

It is not a de Polignac number, because 114013000423 - 29 = 114012999911 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 114013000423.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114013006423) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 14722686 + ... + 14730427.

It is an arithmetic number, because the mean of its divisors is an integer number (11192183320).

Almost surely, 2114013000423 is an apocalyptic number.

114013000423 is a deficient number, since it is larger than the sum of its proper divisors (20293199417).

114013000423 is an equidigital number, since it uses as much as digits as its factorization.

114013000423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29453206 (or 29453199 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 114013000423 its reverse (324000310411), we get a palindrome (438013310834).

The spelling of 114013000423 in words is "one hundred fourteen billion, thirteen million, four hundred twenty-three", and thus it is an aban number.

Divisors: 1 7 49 79 553 3871 29453113 206171791 1443202537 2326795927 16287571489 114013000423