Base | Representation |
---|---|
bin | 10101001111001001… |
… | …00000100100111011 |
3 | 1002102120120001201212 |
4 | 22213210200210323 |
5 | 141322213102113 |
6 | 5123201233335 |
7 | 552351311342 |
oct | 124744404473 |
9 | 32376501655 |
10 | 11401300283 |
11 | 492081171a |
12 | 226233284b |
13 | 10c9102a39 |
14 | 7a22d2b59 |
15 | 46ae0d0a8 |
hex | 2a792093b |
11401300283 has 2 divisors, whose sum is σ = 11401300284. Its totient is φ = 11401300282.
The previous prime is 11401300147. The next prime is 11401300289. The reversal of 11401300283 is 38200310411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11401300283 - 230 = 10327558459 is a prime.
It is not a weakly prime, because it can be changed into another prime (11401300289) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5700650141 + 5700650142.
It is an arithmetic number, because the mean of its divisors is an integer number (5700650142).
Almost surely, 211401300283 is an apocalyptic number.
11401300283 is a deficient number, since it is larger than the sum of its proper divisors (1).
11401300283 is an equidigital number, since it uses as much as digits as its factorization.
11401300283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 11401300283 its reverse (38200310411), we get a palindrome (49601610694).
The spelling of 11401300283 in words is "eleven billion, four hundred one million, three hundred thousand, two hundred eighty-three".
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