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11401301031413 is a prime number
BaseRepresentation
bin1010010111101001001001…
…1111110111100111110101
31111100221202021100021212212
42211322102133313213311
52443244331031001123
640125404013223205
72254500603521666
oct245722237674765
944327667307785
1011401301031413
1136a62a0223487
121341794791b05
136491a446b967
142b5b7c44736d
1514b8923e8878
hexa5e927f79f5

11401301031413 has 2 divisors, whose sum is σ = 11401301031414. Its totient is φ = 11401301031412.

The previous prime is 11401301031397. The next prime is 11401301031433. The reversal of 11401301031413 is 31413010310411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11392359816049 + 8941215364 = 3375257^2 + 94558^2 .

It is a cyclic number.

It is not a de Polignac number, because 11401301031413 - 24 = 11401301031397 is a prime.

It is a super-2 number, since 2×114013010314132 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11401301031433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5700650515706 + 5700650515707.

It is an arithmetic number, because the mean of its divisors is an integer number (5700650515707).

Almost surely, 211401301031413 is an apocalyptic number.

It is an amenable number.

11401301031413 is a deficient number, since it is larger than the sum of its proper divisors (1).

11401301031413 is an equidigital number, since it uses as much as digits as its factorization.

11401301031413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 11401301031413 its reverse (31413010310411), we get a palindrome (42814311341824).

The spelling of 11401301031413 in words is "eleven trillion, four hundred one billion, three hundred one million, thirty-one thousand, four hundred thirteen".