1140132437 has 2 divisors, whose sum is σ = 1140132438. Its totient is φ = 1140132436.

The previous prime is 1140132403. The next prime is 1140132443. The reversal of 1140132437 is 7342310411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1068374596 + 71757841 = 32686^2 + 8471^2 .

It is an emirp because it is prime and its reverse (7342310411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1140132437 - 2¹⁴ = 1140116053 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1140132457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570066218 + 570066219.

It is an arithmetic number, because the mean of its divisors is an integer number (570066219).

Almost surely, 2^1140132437 is an apocalyptic number.

It is an amenable number.

1140132437 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140132437 is an equidigital number, since it uses as much as digits as its factorization.

1140132437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 26.

The square root of 1140132437 is about 33765.8471980195. The cubic root of 1140132437 is about 1044.6843783283.

Adding to 1140132437 its reverse (7342310411), we get a palindrome (8482442848).

The spelling of 1140132437 in words is "one billion, one hundred forty million, one hundred thirty-two thousand, four hundred thirty-seven".