114013403051 has 4 divisors (see below), whose sum is σ = 114883734504. Its totient is φ = 113143071600.

The previous prime is 114013403033. The next prime is 114013403057. The reversal of 114013403051 is 150304310411.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114013403051 - 2¹⁴ = 114013386667 is a prime.

It is a super-2 number, since 2×114013403051² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114013403057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435165530 + ... + 435165791.

It is an arithmetic number, because the mean of its divisors is an integer number (28720933626).

Almost surely, 2^114013403051 is an apocalyptic number.

114013403051 is a deficient number, since it is larger than the sum of its proper divisors (870331453).

114013403051 is an equidigital number, since it uses as much as digits as its factorization.

114013403051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 870331452.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 114013403051 its reverse (150304310411), we get a palindrome (264317713462).

The spelling of 114013403051 in words is "one hundred fourteen billion, thirteen million, four hundred three thousand, fifty-one".