114013410221 has 2 divisors, whose sum is σ = 114013410222. Its totient is φ = 114013410220.

The previous prime is 114013410211. The next prime is 114013410223. The reversal of 114013410221 is 122014310411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 93853386025 + 20160024196 = 306355^2 + 141986^2 .

It is a cyclic number.

It is not a de Polignac number, because 114013410221 - 2¹⁰ = 114013409197 is a prime.

Together with 114013410223, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 114013410193 and 114013410202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114013410223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57006705110 + 57006705111.

It is an arithmetic number, because the mean of its divisors is an integer number (57006705111).

Almost surely, 2^114013410221 is an apocalyptic number.

It is an amenable number.

114013410221 is a deficient number, since it is larger than the sum of its proper divisors (1).

114013410221 is an equidigital number, since it uses as much as digits as its factorization.

114013410221 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 114013410221 its reverse (122014310411), we get a palindrome (236027720632).

The spelling of 114013410221 in words is "one hundred fourteen billion, thirteen million, four hundred ten thousand, two hundred twenty-one".