1140134230035 has 80 divisors (see below), whose sum is σ = 2051777407680. Its totient is φ = 605700944640.

The previous prime is 1140134230033. The next prime is 1140134230043. The reversal of 1140134230035 is 5300324310411.

It is a happy number.

1140134230035 is a `hidden beast` number, since 1 + 14 + 0 + 1 + 342 + 300 + 3 + 5 = 666.

It is not a de Polignac number, because 1140134230035 - 2¹ = 1140134230033 is a prime.

It is a super-2 number, since 2×1140134230035² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 1140134229990 and 1140134230008.

It is not an unprimeable number, because it can be changed into a prime (1140134230031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 147281265 + ... + 147289005.

It is an arithmetic number, because the mean of its divisors is an integer number (25647217596).

Almost surely, 2^{1140134230035} is an apocalyptic number.

1140134230035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

1140134230035 is a deficient number, since it is larger than the sum of its proper divisors (911643177645).

1140134230035 is a wasteful number, since it uses less digits than its factorization.

1140134230035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9130 (or 9121 counting only the distinct ones).

The product of its (nonzero) digits is 4320, while the sum is 27.

Adding to 1140134230035 its reverse (5300324310411), we get a palindrome (6440458540446).

The spelling of 1140134230035 in words is "one trillion, one hundred forty billion, one hundred thirty-four million, two hundred thirty thousand, thirty-five".