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1140134403451 is a prime number
BaseRepresentation
bin10000100101110101010…
…011100101110101111011
311000222212221000201002211
4100211311103211311323
5122134443401402301
62231434233035551
7145241410346101
oct20456523456573
94028787021084
101140134403451
113aa58a16936a
12164b70855bb7
138368b9586b4
143d27b85dc71
151e9ce186051
hex109754e5d7b

1140134403451 has 2 divisors, whose sum is σ = 1140134403452. Its totient is φ = 1140134403450.

The previous prime is 1140134403449. The next prime is 1140134403461. The reversal of 1140134403451 is 1543044310411.

It is a weak prime.

It is an emirp because it is prime and its reverse (1543044310411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1140134403451 - 21 = 1140134403449 is a prime.

Together with 1140134403449, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1140134403461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570067201725 + 570067201726.

It is an arithmetic number, because the mean of its divisors is an integer number (570067201726).

Almost surely, 21140134403451 is an apocalyptic number.

1140134403451 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140134403451 is an equidigital number, since it uses as much as digits as its factorization.

1140134403451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 1140134403451 its reverse (1543044310411), we get a palindrome (2683178713862).

The spelling of 1140134403451 in words is "one trillion, one hundred forty billion, one hundred thirty-four million, four hundred three thousand, four hundred fifty-one".