114013450125 has 32 divisors (see below), whose sum is σ = 210798207360. Its totient is φ = 60807171600.

The previous prime is 114013450093. The next prime is 114013450151. The reversal of 114013450125 is 521054310411.

114013450125 is a `hidden beast` number, since 1 + 1 + 4 + 0 + 134 + 501 + 25 = 666.

It is not a de Polignac number, because 114013450125 - 2⁵ = 114013450093 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16887507 + ... + 16894256.

It is an arithmetic number, because the mean of its divisors is an integer number (6587443980).

Almost surely, 2^114013450125 is an apocalyptic number.

114013450125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

114013450125 is a deficient number, since it is larger than the sum of its proper divisors (96784757235).

114013450125 is an equidigital number, since it uses as much as digits as its factorization.

114013450125 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33781787 (or 33781771 counting only the distinct ones).

The product of its (nonzero) digits is 2400, while the sum is 27.

Adding to 114013450125 its reverse (521054310411), we get a palindrome (635067760536).

The spelling of 114013450125 in words is "one hundred fourteen billion, thirteen million, four hundred fifty thousand, one hundred twenty-five".