114014044303 has 4 divisors (see below), whose sum is σ = 118971176688. Its totient is φ = 109056911920.

The previous prime is 114014044229. The next prime is 114014044379. The reversal of 114014044303 is 303440410411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 303440410411 = 62131 ⋅4883881.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114014044303 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114014044603) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2478566158 + ... + 2478566203.

It is an arithmetic number, because the mean of its divisors is an integer number (29742794172).

Almost surely, 2^114014044303 is an apocalyptic number.

114014044303 is a deficient number, since it is larger than the sum of its proper divisors (4957132385).

114014044303 is an equidigital number, since it uses as much as digits as its factorization.

114014044303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4957132384.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 114014044303 its reverse (303440410411), we get a palindrome (417454454714).

The spelling of 114014044303 in words is "one hundred fourteen billion, fourteen million, forty-four thousand, three hundred three".