11402220113 has 2 divisors, whose sum is σ = 11402220114. Its totient is φ = 11402220112.

The previous prime is 11402220103. The next prime is 11402220119. The reversal of 11402220113 is 31102220411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7735554304 + 3666665809 = 87952^2 + 60553^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11402220113 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11402220091 and 11402220100.

It is not a weakly prime, because it can be changed into another prime (11402220119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701110056 + 5701110057.

It is an arithmetic number, because the mean of its divisors is an integer number (5701110057).

Almost surely, 2^11402220113 is an apocalyptic number.

It is an amenable number.

11402220113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11402220113 is an equidigital number, since it uses as much as digits as its factorization.

11402220113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 11402220113 its reverse (31102220411), we get a palindrome (42504440524).

The spelling of 11402220113 in words is "eleven billion, four hundred two million, two hundred twenty thousand, one hundred thirteen".