11402341127 has 2 divisors, whose sum is σ = 11402341128. Its totient is φ = 11402341126.

The previous prime is 11402341073. The next prime is 11402341129. The reversal of 11402341127 is 72114320411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11402341127 - 2²⁶ = 11335232263 is a prime.

Together with 11402341129, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11402341096 and 11402341105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11402341129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701170563 + 5701170564.

It is an arithmetic number, because the mean of its divisors is an integer number (5701170564).

Almost surely, 2^11402341127 is an apocalyptic number.

11402341127 is a deficient number, since it is larger than the sum of its proper divisors (1).

11402341127 is an equidigital number, since it uses as much as digits as its factorization.

11402341127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1344, while the sum is 26.

Adding to 11402341127 its reverse (72114320411), we get a palindrome (83516661538).

The spelling of 11402341127 in words is "eleven billion, four hundred two million, three hundred forty-one thousand, one hundred twenty-seven".