Base | Representation |
---|---|
bin | 1010010111101110000111… |
… | …0101111011011110101111 |
3 | 1111101002012001012101201012 |
4 | 2211323201311323132233 |
5 | 2443310042321330242 |
6 | 40130144045135435 |
7 | 2254545566426045 |
oct | 245734165733657 |
9 | 44332161171635 |
10 | 11402632214447 |
11 | 36a6913689a51 |
12 | 1341aa655a57b |
13 | 6493571a4226 |
14 | 2b5c67164395 |
15 | 14b91e1e8282 |
hex | a5ee1d7b7af |
11402632214447 has 2 divisors, whose sum is σ = 11402632214448. Its totient is φ = 11402632214446.
The previous prime is 11402632214423. The next prime is 11402632214471. The reversal of 11402632214447 is 74441223620411.
It is a balanced prime because it is at equal distance from previous prime (11402632214423) and next prime (11402632214471).
It is a cyclic number.
It is not a de Polignac number, because 11402632214447 - 228 = 11402363778991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11402632214417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701316107223 + 5701316107224.
It is an arithmetic number, because the mean of its divisors is an integer number (5701316107224).
Almost surely, 211402632214447 is an apocalyptic number.
11402632214447 is a deficient number, since it is larger than the sum of its proper divisors (1).
11402632214447 is an equidigital number, since it uses as much as digits as its factorization.
11402632214447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 258048, while the sum is 41.
Adding to 11402632214447 its reverse (74441223620411), we get a palindrome (85843855834858).
The spelling of 11402632214447 in words is "eleven trillion, four hundred two billion, six hundred thirty-two million, two hundred fourteen thousand, four hundred forty-seven".
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