Base | Representation |
---|---|
bin | 1010010111101111100100… |
… | …0110001001000010100111 |
3 | 1111101010012020021211201111 |
4 | 2211323321012021002213 |
5 | 2443311342204342023 |
6 | 40130250503005451 |
7 | 2254561344434101 |
oct | 245737106110247 |
9 | 44333166254644 |
10 | 11403022340263 |
11 | 36a6aa3920284 |
12 | 1341b95139887 |
13 | 6493b9c692c8 |
14 | 2b5ca2cb8571 |
15 | 14b9435ab00d |
hex | a5ef91890a7 |
11403022340263 has 2 divisors, whose sum is σ = 11403022340264. Its totient is φ = 11403022340262.
The previous prime is 11403022340231. The next prime is 11403022340267. The reversal of 11403022340263 is 36204322030411.
It is a happy number.
11403022340263 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (36204322030411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11403022340263 - 25 = 11403022340231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11403022340267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701511170131 + 5701511170132.
It is an arithmetic number, because the mean of its divisors is an integer number (5701511170132).
Almost surely, 211403022340263 is an apocalyptic number.
11403022340263 is a deficient number, since it is larger than the sum of its proper divisors (1).
11403022340263 is an equidigital number, since it uses as much as digits as its factorization.
11403022340263 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 11403022340263 its reverse (36204322030411), we get a palindrome (47607344370674).
The spelling of 11403022340263 in words is "eleven trillion, four hundred three billion, twenty-two million, three hundred forty thousand, two hundred sixty-three".
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