Base | Representation |
---|---|
bin | 11001111011010111010010… |
… | …101011000001100101011110 |
3 | 112221202012222001111102101102 |
4 | 121323113102223001211132 |
5 | 104421234203014014200 |
6 | 1042304535541113102 |
7 | 33006304044654125 |
oct | 3173272253014536 |
9 | 487665861442342 |
10 | 114030621235550 |
11 | 33374129a082a8 |
12 | 10957a943b8792 |
13 | 4b82070084486 |
14 | 202317bddcabc |
15 | d2b2e8b0b6d5 |
hex | 67b5d2ac195e |
114030621235550 has 48 divisors (see below), whose sum is σ = 212190725643120. Its totient is φ = 45592085360640.
The previous prime is 114030621235543. The next prime is 114030621235571. The reversal of 114030621235550 is 55532126030411.
It is a super-3 number, since 3×1140306212355503 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3173405384 + ... + 3173441316.
It is an arithmetic number, because the mean of its divisors is an integer number (4420640117565).
Almost surely, 2114030621235550 is an apocalyptic number.
114030621235550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
114030621235550 is a deficient number, since it is larger than the sum of its proper divisors (98160104407570).
114030621235550 is a wasteful number, since it uses less digits than its factorization.
114030621235550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62237 (or 62232 counting only the distinct ones).
The product of its (nonzero) digits is 108000, while the sum is 38.
Adding to 114030621235550 its reverse (55532126030411), we get a palindrome (169562747265961).
The spelling of 114030621235550 in words is "one hundred fourteen trillion, thirty billion, six hundred twenty-one million, two hundred thirty-five thousand, five hundred fifty".
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