1140313108037 has 2 divisors, whose sum is σ = 1140313108038. Its totient is φ = 1140313108036.

The previous prime is 1140313108031. The next prime is 1140313108061. The reversal of 1140313108037 is 7308013130411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1128967875841 + 11345232196 = 1062529^2 + 106514^2 .

It is a cyclic number.

It is not a de Polignac number, because 1140313108037 - 2¹⁴ = 1140313091653 is a prime.

It is a super-2 number, since 2×1140313108037² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1140313107994 and 1140313108012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1140313108031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570156554018 + 570156554019.

It is an arithmetic number, because the mean of its divisors is an integer number (570156554019).

Almost surely, 2^{1140313108037} is an apocalyptic number.

It is an amenable number.

1140313108037 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140313108037 is an equidigital number, since it uses as much as digits as its factorization.

1140313108037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 32.

Adding to 1140313108037 its reverse (7308013130411), we get a palindrome (8448326238448).

The spelling of 1140313108037 in words is "one trillion, one hundred forty billion, three hundred thirteen million, one hundred eight thousand, thirty-seven".