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114032141981 is a prime number
BaseRepresentation
bin110101000110011011…
…0000110011010011101
3101220100002121000022222
41222030312012122131
53332014212020411
6124215144315125
711144552133302
oct1521466063235
9356302530288
10114032141981
11443a719805a
121a125172aa5
13a9a3993534
14573a9030a9
152e760bb4db
hex1a8cd8669d

114032141981 has 2 divisors, whose sum is σ = 114032141982. Its totient is φ = 114032141980.

The previous prime is 114032141963. The next prime is 114032141999. The reversal of 114032141981 is 189141230411.

It is a balanced prime because it is at equal distance from previous prime (114032141963) and next prime (114032141999).

It can be written as a sum of positive squares in only one way, i.e., 110018919481 + 4013222500 = 331691^2 + 63350^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114032141981 is a prime.

It is a super-2 number, since 2×1140321419812 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114032141081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57016070990 + 57016070991.

It is an arithmetic number, because the mean of its divisors is an integer number (57016070991).

Almost surely, 2114032141981 is an apocalyptic number.

It is an amenable number.

114032141981 is a deficient number, since it is larger than the sum of its proper divisors (1).

114032141981 is an equidigital number, since it uses as much as digits as its factorization.

114032141981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 35.

The spelling of 114032141981 in words is "one hundred fourteen billion, thirty-two million, one hundred forty-one thousand, nine hundred eighty-one".