Base | Representation |
---|---|
bin | 110101000110011011… |
… | …1100101011010111111 |
3 | 101220100010022210011002 |
4 | 1222030313211122333 |
5 | 3332014311444020 |
6 | 124215200520515 |
7 | 11144555343665 |
oct | 1521467453277 |
9 | 356303283132 |
10 | 114032531135 |
11 | 443a7433476 |
12 | 1a12532013b |
13 | a9a3a9b6c3 |
14 | 573a9a4c35 |
15 | 2e76146975 |
hex | 1a8cde56bf |
114032531135 has 32 divisors (see below), whose sum is σ = 146556000000. Its totient is φ = 84917189376.
The previous prime is 114032531131. The next prime is 114032531161. The reversal of 114032531135 is 531135230411.
It is a cyclic number.
It is not a de Polignac number, because 114032531135 - 22 = 114032531131 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114032531098 and 114032531107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114032531131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15202616 + ... + 15210114.
It is an arithmetic number, because the mean of its divisors is an integer number (4579875000).
Almost surely, 2114032531135 is an apocalyptic number.
114032531135 is a deficient number, since it is larger than the sum of its proper divisors (32523468865).
114032531135 is a wasteful number, since it uses less digits than its factorization.
114032531135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10295.
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 114032531135 its reverse (531135230411), we get a palindrome (645167761546).
The spelling of 114032531135 in words is "one hundred fourteen billion, thirty-two million, five hundred thirty-one thousand, one hundred thirty-five".
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