11403434131 has 4 divisors (see below), whose sum is σ = 12074224392. Its totient is φ = 10732643872.

The previous prime is 11403434129. The next prime is 11403434153. The reversal of 11403434131 is 13143430411.

It is a happy number.

11403434131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11403434131 - 2¹ = 11403434129 is a prime.

It is a super-2 number, since 2×11403434131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11403434096 and 11403434105.

It is not an unprimeable number, because it can be changed into a prime (11403434531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335395105 + ... + 335395138.

It is an arithmetic number, because the mean of its divisors is an integer number (3018556098).

Almost surely, 2^11403434131 is an apocalyptic number.

11403434131 is a deficient number, since it is larger than the sum of its proper divisors (670790261).

11403434131 is an equidigital number, since it uses as much as digits as its factorization.

11403434131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 670790260.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 11403434131 its reverse (13143430411), we get a palindrome (24546864542).

The spelling of 11403434131 in words is "eleven billion, four hundred three million, four hundred thirty-four thousand, one hundred thirty-one".