Base | Representation |
---|---|
bin | 10101001111011001… |
… | …01011110011100111 |
3 | 1002102201120221120201 |
4 | 22213230223303213 |
5 | 141323240142211 |
6 | 5123315211331 |
7 | 552405445522 |
oct | 124754536347 |
9 | 32381527521 |
10 | 11403443431 |
11 | 4921a45916 |
12 | 2262ba6b47 |
13 | 10c96a3383 |
14 | 7a26cdbb9 |
15 | 46b1d30c1 |
hex | 2a7b2bce7 |
11403443431 has 2 divisors, whose sum is σ = 11403443432. Its totient is φ = 11403443430.
The previous prime is 11403443419. The next prime is 11403443449. The reversal of 11403443431 is 13434430411.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11403443431 - 215 = 11403410663 is a prime.
It is a super-2 number, since 2×114034434312 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11403443431.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11403443231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701721715 + 5701721716.
It is an arithmetic number, because the mean of its divisors is an integer number (5701721716).
Almost surely, 211403443431 is an apocalyptic number.
11403443431 is a deficient number, since it is larger than the sum of its proper divisors (1).
11403443431 is an equidigital number, since it uses as much as digits as its factorization.
11403443431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 11403443431 its reverse (13434430411), we get a palindrome (24837873842).
The spelling of 11403443431 in words is "eleven billion, four hundred three million, four hundred forty-three thousand, four hundred thirty-one".
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