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114040113 = 3113455761
BaseRepresentation
bin1101100110000…
…01110100110001
321221120211121220
412303001310301
5213143240423
615152135253
72553216315
oct663016461
9257524556
10114040113
1159411030
1232237529
131a81b275
1411207b45
15a0299e3
hex6cc1d31

114040113 has 8 divisors (see below), whose sum is σ = 165876576. Its totient is φ = 69115200.

The previous prime is 114040111. The next prime is 114040123. The reversal of 114040113 is 311040411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 114040113 - 21 = 114040111 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 114040092 and 114040101.

It is not an unprimeable number, because it can be changed into a prime (114040111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1727848 + ... + 1727913.

It is an arithmetic number, because the mean of its divisors is an integer number (20734572).

Almost surely, 2114040113 is an apocalyptic number.

It is an amenable number.

114040113 is a deficient number, since it is larger than the sum of its proper divisors (51836463).

114040113 is a wasteful number, since it uses less digits than its factorization.

114040113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3455775.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 114040113 is about 10678.9565501504. The cubic root of 114040113 is about 484.9376233238.

Adding to 114040113 its reverse (311040411), we get a palindrome (425080524).

The spelling of 114040113 in words is "one hundred fourteen million, forty thousand, one hundred thirteen".

Divisors: 1 3 11 33 3455761 10367283 38013371 114040113