114043314111 has 4 divisors (see below), whose sum is σ = 152057752152. Its totient is φ = 76028876072.

The previous prime is 114043314107. The next prime is 114043314137. The reversal of 114043314111 is 111413340411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111413340411 = 3 ⋅37137780137.

It is a cyclic number.

It is not a de Polignac number, because 114043314111 - 2² = 114043314107 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114043314611) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19007219016 + ... + 19007219021.

It is an arithmetic number, because the mean of its divisors is an integer number (38014438038).

Almost surely, 2^114043314111 is an apocalyptic number.

114043314111 is a deficient number, since it is larger than the sum of its proper divisors (38014438041).

114043314111 is an equidigital number, since it uses as much as digits as its factorization.

114043314111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38014438040.

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 114043314111 its reverse (111413340411), we get a palindrome (225456654522).

The spelling of 114043314111 in words is "one hundred fourteen billion, forty-three million, three hundred fourteen thousand, one hundred eleven".