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114043975973 is a prime number
BaseRepresentation
bin110101000110110001…
…1001111100100100101
3101220100220212020111222
41222031203033210211
53332030224212343
6124220250110125
711145054541604
oct1521543174445
9356326766458
10114043975973
1144402940114
121a12911b345
13a9a6277ab5
14573c303a3b
152e77157a68
hex1a8d8cf925

114043975973 has 2 divisors, whose sum is σ = 114043975974. Its totient is φ = 114043975972.

The previous prime is 114043975967. The next prime is 114043975979. The reversal of 114043975973 is 379579340411.

It is a balanced prime because it is at equal distance from previous prime (114043975967) and next prime (114043975979).

It can be written as a sum of positive squares in only one way, i.e., 94702676644 + 19341299329 = 307738^2 + 139073^2 .

It is a cyclic number.

It is not a de Polignac number, because 114043975973 - 26 = 114043975909 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114043975979) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57021987986 + 57021987987.

It is an arithmetic number, because the mean of its divisors is an integer number (57021987987).

Almost surely, 2114043975973 is an apocalyptic number.

It is an amenable number.

114043975973 is a deficient number, since it is larger than the sum of its proper divisors (1).

114043975973 is an equidigital number, since it uses as much as digits as its factorization.

114043975973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2857680, while the sum is 53.

The spelling of 114043975973 in words is "one hundred fourteen billion, forty-three million, nine hundred seventy-five thousand, nine hundred seventy-three".