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11404412402 = 25702206201
BaseRepresentation
bin10101001111100000…
…11000010111110010
31002102210102011202112
422213300120113302
5141324012144102
65123352045322
7552416622515
oct124760302762
932383364675
1011404412402
114922547919
122263393842
1310c9952426
147a28a2d7c
1546b325252
hex2a7c185f2

11404412402 has 4 divisors (see below), whose sum is σ = 17106618606. Its totient is φ = 5702206200.

The previous prime is 11404412353. The next prime is 11404412423. The reversal of 11404412402 is 20421440411.

11404412402 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 20421440411 = 23387645667.

It can be written as a sum of positive squares in only one way, i.e., 10702109401 + 702303001 = 103451^2 + 26501^2 .

It is a super-3 number, since 3×114044124023 (a number of 31 digits) contains 333 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2851103099 + ... + 2851103102.

Almost surely, 211404412402 is an apocalyptic number.

11404412402 is a deficient number, since it is larger than the sum of its proper divisors (5702206204).

11404412402 is an equidigital number, since it uses as much as digits as its factorization.

11404412402 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5702206203.

The product of its (nonzero) digits is 1024, while the sum is 23.

Adding to 11404412402 its reverse (20421440411), we get a palindrome (31825852813).

The spelling of 11404412402 in words is "eleven billion, four hundred four million, four hundred twelve thousand, four hundred two".

Divisors: 1 2 5702206201 11404412402