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114053131231 = 13351913123
BaseRepresentation
bin110101000111000011…
…0001010101111011111
3101220101120002101011121
41222032012022233133
53332040100144411
6124221214231411
711145225422404
oct1521606125737
9356346071147
10114053131231
1144408023646
121a1301b5567
13a9a8132000
14573d6082ab
152e77d65571
hex1a8e18abdf

114053131231 has 8 divisors (see below), whose sum is σ = 123553235120. Its totient is φ = 105279811416.

The previous prime is 114053131229. The next prime is 114053131259. The reversal of 114053131231 is 132131350411.

It is not a de Polignac number, because 114053131231 - 21 = 114053131229 is a prime.

It is a super-2 number, since 2×1140531312312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114053131196 and 114053131205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114053131831) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25954365 + ... + 25958758.

It is an arithmetic number, because the mean of its divisors is an integer number (15444154390).

Almost surely, 2114053131231 is an apocalyptic number.

114053131231 is a deficient number, since it is larger than the sum of its proper divisors (9500103889).

114053131231 is an frugal number, since it uses more digits than its factorization.

114053131231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51913162 (or 51913136 counting only the distinct ones).

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 114053131231 its reverse (132131350411), we get a palindrome (246184481642).

The spelling of 114053131231 in words is "one hundred fourteen billion, fifty-three million, one hundred thirty-one thousand, two hundred thirty-one".

Divisors: 1 13 169 2197 51913123 674870599 8773317787 114053131231