Base | Representation |
---|---|
bin | 10101001111110010… |
… | …10111111100010111 |
3 | 1002102221211221200212 |
4 | 22213321113330113 |
5 | 141330113114233 |
6 | 5123514400035 |
7 | 552445642022 |
oct | 124771277427 |
9 | 32387757625 |
10 | 11406769943 |
11 | 49239080a8 |
12 | 226413001b |
13 | 10ca29951a |
14 | 7a2d181b9 |
15 | 46b63da48 |
hex | 2a7e57f17 |
11406769943 has 2 divisors, whose sum is σ = 11406769944. Its totient is φ = 11406769942.
The previous prime is 11406769921. The next prime is 11406769961. The reversal of 11406769943 is 34996760411.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (34996760411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11406769943 - 230 = 10333028119 is a prime.
It is a super-2 number, since 2×114067699432 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11406769891 and 11406769900.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11406709943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5703384971 + 5703384972.
It is an arithmetic number, because the mean of its divisors is an integer number (5703384972).
Almost surely, 211406769943 is an apocalyptic number.
11406769943 is a deficient number, since it is larger than the sum of its proper divisors (1).
11406769943 is an equidigital number, since it uses as much as digits as its factorization.
11406769943 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 979776, while the sum is 50.
The spelling of 11406769943 in words is "eleven billion, four hundred six million, seven hundred sixty-nine thousand, nine hundred forty-three".
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