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11410000000039 is a prime number
BaseRepresentation
bin1010011000001001100011…
…1111110011010000100111
31111101210012111222200111001
42212002120333303100213
52443420140000000124
640133403122254131
72255226302526364
oct246023077632047
944353174880431
1011410000000039
1136a9a545a6353
121343401ab7347
13649c5c74c884
142b636589b46b
1514bc00e60b44
hexa6098ff3427

11410000000039 has 2 divisors, whose sum is σ = 11410000000040. Its totient is φ = 11410000000038.

The previous prime is 11409999999977. The next prime is 11410000000093. The reversal of 11410000000039 is 93000000001411.

It is a happy number.

11410000000039 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (11410000000093) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11410000000039 - 227 = 11409865782311 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11409999999953 and 11410000000025.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11410000000099) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705000000019 + 5705000000020.

It is an arithmetic number, because the mean of its divisors is an integer number (5705000000020).

Almost surely, 211410000000039 is an apocalyptic number.

11410000000039 is a deficient number, since it is larger than the sum of its proper divisors (1).

11410000000039 is an equidigital number, since it uses as much as digits as its factorization.

11410000000039 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 19.

The spelling of 11410000000039 in words is "eleven trillion, four hundred ten billion, thirty-nine", and thus it is an aban number.