Base | Representation |
---|---|
bin | 10000100110101001000… |
… | …101000001100101101011 |
3 | 11001002010110102222210201 |
4 | 100212221011001211223 |
5 | 122143233232001141 |
6 | 2232100342053031 |
7 | 145302055323046 |
oct | 20465105014553 |
9 | 4032113388721 |
10 | 1141003000171 |
11 | 3aa9954a19a1 |
12 | 16517371a177 |
13 | 837998a8458 |
14 | 3d320d63c5d |
15 | 1ea3055d031 |
hex | 109a914196b |
1141003000171 has 2 divisors, whose sum is σ = 1141003000172. Its totient is φ = 1141003000170.
The previous prime is 1141003000153. The next prime is 1141003000211. The reversal of 1141003000171 is 1710003001411.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1141003000171 - 29 = 1141002999659 is a prime.
It is not a weakly prime, because it can be changed into another prime (1141003000271) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570501500085 + 570501500086.
It is an arithmetic number, because the mean of its divisors is an integer number (570501500086).
Almost surely, 21141003000171 is an apocalyptic number.
1141003000171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141003000171 is an equidigital number, since it uses as much as digits as its factorization.
1141003000171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 19.
Adding to 1141003000171 its reverse (1710003001411), we get a palindrome (2851006001582).
The spelling of 1141003000171 in words is "one trillion, one hundred forty-one billion, three million, one hundred seventy-one", and thus it is an aban number.
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