Base | Representation |
---|---|
bin | 11001111100011001110011… |
… | …000010001101000011100110 |
3 | 112222000001021201211120212201 |
4 | 121330121303002031003212 |
5 | 104423421424433040032 |
6 | 1042401425515205114 |
7 | 33014412462112420 |
oct | 3174316302150346 |
9 | 488001251746781 |
10 | 114102031143142 |
11 | 333a1443a45859 |
12 | 109698a344679a |
13 | 4b88a10639073 |
14 | 20267d3d85810 |
15 | d2d0c7dbc8e7 |
hex | 67c67308d0e6 |
114102031143142 has 8 divisors (see below), whose sum is σ = 195603481959696. Its totient is φ = 48900870489912.
The previous prime is 114102031143119. The next prime is 114102031143241. The reversal of 114102031143142 is 241341130201411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a self number, because there is not a number n which added to its sum of digits gives 114102031143142.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4075072540813 + ... + 4075072540840.
It is an arithmetic number, because the mean of its divisors is an integer number (24450435244962).
Almost surely, 2114102031143142 is an apocalyptic number.
114102031143142 is a deficient number, since it is larger than the sum of its proper divisors (81501450816554).
114102031143142 is an equidigital number, since it uses as much as digits as its factorization.
114102031143142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8150145081662.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 114102031143142 its reverse (241341130201411), we get a palindrome (355443161344553).
The spelling of 114102031143142 in words is "one hundred fourteen trillion, one hundred two billion, thirty-one million, one hundred forty-three thousand, one hundred forty-two".
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