Base | Representation |
---|---|
bin | 1010011000001101101010… |
… | …0100011110101110011111 |
3 | 1111101220001012002021222112 |
4 | 2212003122210132232133 |
5 | 2443424413113244203 |
6 | 40134104222104235 |
7 | 2255265461522042 |
oct | 246033244365637 |
9 | 44356035067875 |
10 | 11411100134303 |
11 | 36aa4695a2521 |
12 | 134366a41b07b |
13 | 64a0a66496ac |
14 | 2b642ba32c59 |
15 | 14bc678216d8 |
hex | a60da91eb9f |
11411100134303 has 4 divisors (see below), whose sum is σ = 11498207769048. Its totient is φ = 11323992499560.
The previous prime is 11411100134293. The next prime is 11411100134309. The reversal of 11411100134303 is 30343100111411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11411100134303 - 212 = 11411100130207 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11411100134309) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43553817176 + ... + 43553817437.
It is an arithmetic number, because the mean of its divisors is an integer number (2874551942262).
Almost surely, 211411100134303 is an apocalyptic number.
11411100134303 is a deficient number, since it is larger than the sum of its proper divisors (87107634745).
11411100134303 is an equidigital number, since it uses as much as digits as its factorization.
11411100134303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 87107634744.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 11411100134303 its reverse (30343100111411), we get a palindrome (41754200245714).
The spelling of 11411100134303 in words is "eleven trillion, four hundred eleven billion, one hundred million, one hundred thirty-four thousand, three hundred three".
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