Base | Representation |
---|---|
bin | 10101010000010011… |
… | …11010000110001110 |
3 | 1002110021000011002202 |
4 | 22220021322012032 |
5 | 141332220313032 |
6 | 5124151321502 |
7 | 552530533124 |
oct | 125011720616 |
9 | 32407004082 |
10 | 11411104142 |
11 | 49262a8489 |
12 | 2265680292 |
13 | 10cb156239 |
14 | 7a3725914 |
15 | 46bbe7d62 |
hex | 2a827a18e |
11411104142 has 4 divisors (see below), whose sum is σ = 17116656216. Its totient is φ = 5705552070.
The previous prime is 11411104127. The next prime is 11411104163. The reversal of 11411104142 is 24140111411.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24140111411 = 13 ⋅1856931647.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2852776034 + ... + 2852776037.
It is an arithmetic number, because the mean of its divisors is an integer number (4279164054).
Almost surely, 211411104142 is an apocalyptic number.
11411104142 is a deficient number, since it is larger than the sum of its proper divisors (5705552074).
11411104142 is an equidigital number, since it uses as much as digits as its factorization.
11411104142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5705552073.
The product of its (nonzero) digits is 128, while the sum is 20.
Adding to 11411104142 its reverse (24140111411), we get a palindrome (35551215553).
The spelling of 11411104142 in words is "eleven billion, four hundred eleven million, one hundred four thousand, one hundred forty-two".
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