Base | Representation |
---|---|
bin | 1010011000001110000100… |
… | …1011111010000010110111 |
3 | 1111101220022220221121201111 |
4 | 2212003201023322002313 |
5 | 2443430130022224421 |
6 | 40134123225135451 |
7 | 2255301310143526 |
oct | 246034113720267 |
9 | 44356286847644 |
10 | 11411211133111 |
11 | 36aa516216579 |
12 | 134369b62a587 |
13 | 64a0c364156a |
14 | 2b643c6884bd |
15 | 14bc72449ee1 |
hex | a60e12fa0b7 |
11411211133111 has 2 divisors, whose sum is σ = 11411211133112. Its totient is φ = 11411211133110.
The previous prime is 11411211133079. The next prime is 11411211133183. The reversal of 11411211133111 is 11133111211411.
It is a m-pointer prime, because the next prime (11411211133183) can be obtained adding 11411211133111 to its product of digits (72).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11411211133111 - 25 = 11411211133079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11411211136111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705605566555 + 5705605566556.
It is an arithmetic number, because the mean of its divisors is an integer number (5705605566556).
Almost surely, 211411211133111 is an apocalyptic number.
11411211133111 is a deficient number, since it is larger than the sum of its proper divisors (1).
11411211133111 is an equidigital number, since it uses as much as digits as its factorization.
11411211133111 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 72, while the sum is 22.
Adding to 11411211133111 its reverse (11133111211411), we get a palindrome (22544322344522).
The spelling of 11411211133111 in words is "eleven trillion, four hundred eleven billion, two hundred eleven million, one hundred thirty-three thousand, one hundred eleven".
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