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11411211133111 is a prime number
BaseRepresentation
bin1010011000001110000100…
…1011111010000010110111
31111101220022220221121201111
42212003201023322002313
52443430130022224421
640134123225135451
72255301310143526
oct246034113720267
944356286847644
1011411211133111
1136aa516216579
12134369b62a587
1364a0c364156a
142b643c6884bd
1514bc72449ee1
hexa60e12fa0b7

11411211133111 has 2 divisors, whose sum is σ = 11411211133112. Its totient is φ = 11411211133110.

The previous prime is 11411211133079. The next prime is 11411211133183. The reversal of 11411211133111 is 11133111211411.

It is a m-pointer prime, because the next prime (11411211133183) can be obtained adding 11411211133111 to its product of digits (72).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11411211133111 - 25 = 11411211133079 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11411211136111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705605566555 + 5705605566556.

It is an arithmetic number, because the mean of its divisors is an integer number (5705605566556).

Almost surely, 211411211133111 is an apocalyptic number.

11411211133111 is a deficient number, since it is larger than the sum of its proper divisors (1).

11411211133111 is an equidigital number, since it uses as much as digits as its factorization.

11411211133111 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 72, while the sum is 22.

Adding to 11411211133111 its reverse (11133111211411), we get a palindrome (22544322344522).

The spelling of 11411211133111 in words is "eleven trillion, four hundred eleven billion, two hundred eleven million, one hundred thirty-three thousand, one hundred eleven".