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114113551 is a prime number
BaseRepresentation
bin1101100110100…
…11110000001111
321221201120100211
412303103300033
5213203113201
615153503251
72553643366
oct663236017
9257646324
10114113551
1159461222
1232271b27
131a845816
14112267dd
15a041651
hex6cd3c0f

114113551 has 2 divisors, whose sum is σ = 114113552. Its totient is φ = 114113550.

The previous prime is 114113497. The next prime is 114113567. The reversal of 114113551 is 155311411.

It is a strong prime.

It is an emirp because it is prime and its reverse (155311411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114113551 - 27 = 114113423 is a prime.

It is a Chen prime.

It is a plaindrome in base 14.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114113651) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57056775 + 57056776.

It is an arithmetic number, because the mean of its divisors is an integer number (57056776).

Almost surely, 2114113551 is an apocalyptic number.

114113551 is a deficient number, since it is larger than the sum of its proper divisors (1).

114113551 is an equidigital number, since it uses as much as digits as its factorization.

114113551 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 300, while the sum is 22.

The square root of 114113551 is about 10682.3944413226. The cubic root of 114113551 is about 485.0416954978.

Adding to 114113551 its reverse (155311411), we get a palindrome (269424962).

The spelling of 114113551 in words is "one hundred fourteen million, one hundred thirteen thousand, five hundred fifty-one".