Base | Representation |
---|---|
bin | 110101001000110111… |
… | …1100011101101000111 |
3 | 101220112211012201211012 |
4 | 1222101233203231013 |
5 | 3332201231004111 |
6 | 124231241432435 |
7 | 11146600441115 |
oct | 1522157435507 |
9 | 356484181735 |
10 | 114114313031 |
11 | 44439611414 |
12 | 1a14879b71b |
13 | a9b7a03b64 |
14 | 57477b2ab5 |
15 | 2e7d3ed48b |
hex | 1a91be3b47 |
114114313031 has 2 divisors, whose sum is σ = 114114313032. Its totient is φ = 114114313030.
The previous prime is 114114312973. The next prime is 114114313039. The reversal of 114114313031 is 130313411411.
It is a strong prime.
It is an emirp because it is prime and its reverse (130313411411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114114313031 - 230 = 113040571207 is a prime.
It is a super-2 number, since 2×1141143130312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 114114312988 and 114114313006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114114313039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57057156515 + 57057156516.
It is an arithmetic number, because the mean of its divisors is an integer number (57057156516).
Almost surely, 2114114313031 is an apocalyptic number.
114114313031 is a deficient number, since it is larger than the sum of its proper divisors (1).
114114313031 is an equidigital number, since it uses as much as digits as its factorization.
114114313031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 114114313031 its reverse (130313411411), we get a palindrome (244427724442).
The spelling of 114114313031 in words is "one hundred fourteen billion, one hundred fourteen million, three hundred thirteen thousand, thirty-one".
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