Search a number
-
+
114115433 = 3119119273
BaseRepresentation
bin1101100110101…
…00001101101001
321221201122221112
412303110031221
5213203143213
615153520105
72553652025
oct663241551
9257648845
10114115433
1159462683
1232273035
131a846633
1411227385
15a041ea8
hex6cd4369

114115433 has 8 divisors (see below), whose sum is σ = 118419456. Its totient is φ = 109850400.

The previous prime is 114115427. The next prime is 114115447. The reversal of 114115433 is 334511411.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 114115433 - 214 = 114099049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114115399 and 114115408.

It is not an unprimeable number, because it can be changed into a prime (114115403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3716 + ... + 15557.

It is an arithmetic number, because the mean of its divisors is an integer number (14802432).

Almost surely, 2114115433 is an apocalyptic number.

It is an amenable number.

114115433 is a deficient number, since it is larger than the sum of its proper divisors (4304023).

114115433 is a wasteful number, since it uses less digits than its factorization.

114115433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19495.

The product of its digits is 720, while the sum is 23.

The square root of 114115433 is about 10682.4825298242. The cubic root of 114115433 is about 485.0443619747.

Adding to 114115433 its reverse (334511411), we get a palindrome (448626844).

The spelling of 114115433 in words is "one hundred fourteen million, one hundred fifteen thousand, four hundred thirty-three".

Divisors: 1 31 191 5921 19273 597463 3681143 114115433