114120035 has 4 divisors (see below), whose sum is σ = 136944048. Its totient is φ = 91296024.

The previous prime is 114120029. The next prime is 114120067. The reversal of 114120035 is 530021411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 530021411 = 37 ⋅14324903.

It is a cyclic number.

It is not a de Polignac number, because 114120035 - 2⁸ = 114119779 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114119995 and 114120022.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11411999 + ... + 11412008.

It is an arithmetic number, because the mean of its divisors is an integer number (34236012).

Almost surely, 2^114120035 is an apocalyptic number.

114120035 is a deficient number, since it is larger than the sum of its proper divisors (22824013).

114120035 is an equidigital number, since it uses as much as digits as its factorization.

114120035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22824012.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 114120035 is about 10682.6979270220. The cubic root of 114120035 is about 485.0508821099.

Adding to 114120035 its reverse (530021411), we get a palindrome (644141446).

The spelling of 114120035 in words is "one hundred fourteen million, one hundred twenty thousand, thirty-five".