Base | Representation |
---|---|
bin | 10101010000011011… |
… | …01101100000011011 |
3 | 1002110022212210201212 |
4 | 22220031231200123 |
5 | 141332444214042 |
6 | 5124224533335 |
7 | 552542154626 |
oct | 125015554033 |
9 | 32408783655 |
10 | 11412101147 |
11 | 4926919557 |
12 | 2265a8124b |
13 | 10cb414c95 |
14 | 7a3904dbd |
15 | 46bd43482 |
hex | 2a836d81b |
11412101147 has 2 divisors, whose sum is σ = 11412101148. Its totient is φ = 11412101146.
The previous prime is 11412101101. The next prime is 11412101209. The reversal of 11412101147 is 74110121411.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11412101147 - 210 = 11412100123 is a prime.
It is not a weakly prime, because it can be changed into another prime (11412101747) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706050573 + 5706050574.
It is an arithmetic number, because the mean of its divisors is an integer number (5706050574).
Almost surely, 211412101147 is an apocalyptic number.
11412101147 is a deficient number, since it is larger than the sum of its proper divisors (1).
11412101147 is an equidigital number, since it uses as much as digits as its factorization.
11412101147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 23.
Adding to 11412101147 its reverse (74110121411), we get a palindrome (85522222558).
The spelling of 11412101147 in words is "eleven billion, four hundred twelve million, one hundred one thousand, one hundred forty-seven".
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