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114121022134135 = 534748965683243
BaseRepresentation
bin11001111100101011011110…
…111111000101011101110111
3112222001212022020201212222111
4121330223132333011131313
5104424224323131243020
61042414250202111451
733015654212634202
oct3174533677053567
9488055266655874
10114121022134135
11333a94a9958435
12109715034ab587
134b8a748c71043
1420276b6256939
15d2d83a277d5a
hex67cadefc5777

114121022134135 has 8 divisors (see below), whose sum is σ = 136945622745360. Its totient is φ = 91296553584384.

The previous prime is 114121022134103. The next prime is 114121022134237. The reversal of 114121022134135 is 531431220121411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 114121022134135 - 25 = 114121022134103 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114121022134097 and 114121022134106.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31104177 + ... + 34579066.

It is an arithmetic number, because the mean of its divisors is an integer number (17118202843170).

Almost surely, 2114121022134135 is an apocalyptic number.

114121022134135 is a deficient number, since it is larger than the sum of its proper divisors (22824600611225).

114121022134135 is an equidigital number, since it uses as much as digits as its factorization.

114121022134135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66030737.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 114121022134135 its reverse (531431220121411), we get a palindrome (645552242255546).

The spelling of 114121022134135 in words is "one hundred fourteen trillion, one hundred twenty-one billion, twenty-two million, one hundred thirty-four thousand, one hundred thirty-five".

Divisors: 1 5 347489 1737445 65683243 328416215 22824204426827 114121022134135