Base | Representation |
---|---|
bin | 11001111100101011011110… |
… | …111111000101011101110111 |
3 | 112222001212022020201212222111 |
4 | 121330223132333011131313 |
5 | 104424224323131243020 |
6 | 1042414250202111451 |
7 | 33015654212634202 |
oct | 3174533677053567 |
9 | 488055266655874 |
10 | 114121022134135 |
11 | 333a94a9958435 |
12 | 109715034ab587 |
13 | 4b8a748c71043 |
14 | 20276b6256939 |
15 | d2d83a277d5a |
hex | 67cadefc5777 |
114121022134135 has 8 divisors (see below), whose sum is σ = 136945622745360. Its totient is φ = 91296553584384.
The previous prime is 114121022134103. The next prime is 114121022134237. The reversal of 114121022134135 is 531431220121411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 114121022134135 - 25 = 114121022134103 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114121022134097 and 114121022134106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31104177 + ... + 34579066.
It is an arithmetic number, because the mean of its divisors is an integer number (17118202843170).
Almost surely, 2114121022134135 is an apocalyptic number.
114121022134135 is a deficient number, since it is larger than the sum of its proper divisors (22824600611225).
114121022134135 is an equidigital number, since it uses as much as digits as its factorization.
114121022134135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66030737.
The product of its (nonzero) digits is 5760, while the sum is 31.
Adding to 114121022134135 its reverse (531431220121411), we get a palindrome (645552242255546).
The spelling of 114121022134135 in words is "one hundred fourteen trillion, one hundred twenty-one billion, twenty-two million, one hundred thirty-four thousand, one hundred thirty-five".
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