Base | Representation |
---|---|
bin | 11001111100101011110111… |
… | …011111111111000110101111 |
3 | 112222001220100220121222011120 |
4 | 121330223313133333012233 |
5 | 104424231143423141030 |
6 | 1042414355053152023 |
7 | 33016000335510111 |
oct | 3174536737770657 |
9 | 488056326558146 |
10 | 114121433412015 |
11 | 333a96a0026607 |
12 | 109715b918b613 |
13 | 4b8a7b3230a33 |
14 | 2027714b153b1 |
15 | d2d861418010 |
hex | 67caf77ff1af |
114121433412015 has 64 divisors (see below), whose sum is σ = 187882618936320. Its totient is φ = 59115806346240.
The previous prime is 114121433412001. The next prime is 114121433412089. The reversal of 114121433412015 is 510214334121411.
It is not a de Polignac number, because 114121433412015 - 28 = 114121433411759 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 128707566 + ... + 129591204.
It is an arithmetic number, because the mean of its divisors is an integer number (2935665920880).
Almost surely, 2114121433412015 is an apocalyptic number.
114121433412015 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
114121433412015 is a deficient number, since it is larger than the sum of its proper divisors (73761185524305).
114121433412015 is a wasteful number, since it uses less digits than its factorization.
114121433412015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 884624.
The product of its (nonzero) digits is 11520, while the sum is 33.
Adding to 114121433412015 its reverse (510214334121411), we get a palindrome (624335767533426).
The spelling of 114121433412015 in words is "one hundred fourteen trillion, one hundred twenty-one billion, four hundred thirty-three million, four hundred twelve thousand, fifteen".
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