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1141222205455 = 5593868549849
BaseRepresentation
bin10000100110110110001…
…001001110100000001111
311001002200201220202220221
4100212312021032200033
5122144210341033310
62232134212252211
7145310356456363
oct20466611164017
94032621822827
101141222205455
113aaa98202092
12165215011067
1383803128217
143d3421052a3
151ea4490cada
hex109b624e80f

1141222205455 has 8 divisors (see below), whose sum is σ = 1392677946000. Its totient is φ = 897503564736.

The previous prime is 1141222205441. The next prime is 1141222205477. The reversal of 1141222205455 is 5545022221411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1141222205455 - 29 = 1141222204943 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1141222205455.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1934274630 + ... + 1934275219.

It is an arithmetic number, because the mean of its divisors is an integer number (174084743250).

Almost surely, 21141222205455 is an apocalyptic number.

1141222205455 is a deficient number, since it is larger than the sum of its proper divisors (251455740545).

1141222205455 is an equidigital number, since it uses as much as digits as its factorization.

1141222205455 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3868549913.

The product of its (nonzero) digits is 32000, while the sum is 34.

Adding to 1141222205455 its reverse (5545022221411), we get a palindrome (6686244426866).

The spelling of 1141222205455 in words is "one trillion, one hundred forty-one billion, two hundred twenty-two million, two hundred five thousand, four hundred fifty-five".

Divisors: 1 5 59 295 3868549849 19342749245 228244441091 1141222205455