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114122433239 is a prime number
BaseRepresentation
bin110101001001000111…
…0100010001011010111
3101220120101111021122122
41222102032202023113
53332210320330424
6124232131450155
711150026451153
oct1522216421327
9356511437578
10114122433239
1144443158231
121a14b45695b
13a9b95b7c09
1457488c8063
152e7dea445e
hex1a923a22d7

114122433239 has 2 divisors, whose sum is σ = 114122433240. Its totient is φ = 114122433238.

The previous prime is 114122433223. The next prime is 114122433241. The reversal of 114122433239 is 932334221411.

It is a strong prime.

It is an emirp because it is prime and its reverse (932334221411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114122433239 - 24 = 114122433223 is a prime.

It is a super-2 number, since 2×1141224332392 (a number of 23 digits) contains 22 as substring.

Together with 114122433241, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 114122433199 and 114122433208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114122433289) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57061216619 + 57061216620.

It is an arithmetic number, because the mean of its divisors is an integer number (57061216620).

Almost surely, 2114122433239 is an apocalyptic number.

114122433239 is a deficient number, since it is larger than the sum of its proper divisors (1).

114122433239 is an equidigital number, since it uses as much as digits as its factorization.

114122433239 is an evil number, because the sum of its binary digits is even.

The product of its digits is 31104, while the sum is 35.

The spelling of 114122433239 in words is "one hundred fourteen billion, one hundred twenty-two million, four hundred thirty-three thousand, two hundred thirty-nine".