114123000001 has 4 divisors (see below), whose sum is σ = 114199955632. Its totient is φ = 114046044372.

The previous prime is 114122999933. The next prime is 114123000037. The reversal of 114123000001 is 100000321411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 100000321411 = 47 ⋅2127666413.

It is a cyclic number.

It is not a de Polignac number, because 114123000001 - 2⁷ = 114122999873 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114123000301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38475591 + ... + 38478556.

It is an arithmetic number, because the mean of its divisors is an integer number (28549988908).

Almost surely, 2^114123000001 is an apocalyptic number.

It is an amenable number.

114123000001 is a deficient number, since it is larger than the sum of its proper divisors (76955631).

114123000001 is an equidigital number, since it uses as much as digits as its factorization.

114123000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 76955630.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 114123000001 its reverse (100000321411), we get a palindrome (214123321412).

The spelling of 114123000001 in words is "one hundred fourteen billion, one hundred twenty-three million, one", and thus it is an aban number.