Base | Representation |
---|---|
bin | 110101001001001000… |
… | …0111100100011000111 |
3 | 101220120102200102000022 |
4 | 1222102100330203013 |
5 | 3332211001044133 |
6 | 124232153205355 |
7 | 11150035023464 |
oct | 1522220744307 |
9 | 356512612008 |
10 | 114123065543 |
11 | 4444354a2a3 |
12 | 1a14b70085b |
13 | a9b9779966 |
14 | 5748a1066b |
15 | 2e7e07b998 |
hex | 1a9243c8c7 |
114123065543 has 2 divisors, whose sum is σ = 114123065544. Its totient is φ = 114123065542.
The previous prime is 114123065503. The next prime is 114123065561. The reversal of 114123065543 is 345560321411.
It is a strong prime.
It is an emirp because it is prime and its reverse (345560321411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114123065543 - 234 = 96943196359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114123065503) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57061532771 + 57061532772.
It is an arithmetic number, because the mean of its divisors is an integer number (57061532772).
Almost surely, 2114123065543 is an apocalyptic number.
114123065543 is a deficient number, since it is larger than the sum of its proper divisors (1).
114123065543 is an equidigital number, since it uses as much as digits as its factorization.
114123065543 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 114123065543 its reverse (345560321411), we get a palindrome (459683386954).
The spelling of 114123065543 in words is "one hundred fourteen billion, one hundred twenty-three million, sixty-five thousand, five hundred forty-three".
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