11412314433 has 24 divisors (see below), whose sum is σ = 18002537280. Its totient is φ = 6924042720.

The previous prime is 11412314401. The next prime is 11412314449. The reversal of 11412314433 is 33441321411.

It is not a de Polignac number, because 11412314433 - 2⁵ = 11412314401 is a prime.

It is a super-2 number, since 2×11412314433² (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11412314397 and 11412314406.

It is not an unprimeable number, because it can be changed into a prime (11412314533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 678603 + ... + 695216.

It is an arithmetic number, because the mean of its divisors is an integer number (750105720).

Almost surely, 2^11412314433 is an apocalyptic number.

11412314433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11412314433 is a deficient number, since it is larger than the sum of its proper divisors (6590222847).

11412314433 is a wasteful number, since it uses less digits than its factorization.

11412314433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1373909 (or 1373906 counting only the distinct ones).

The product of its digits is 3456, while the sum is 27.

Adding to 11412314433 its reverse (33441321411), we get a palindrome (44853635844).

The spelling of 11412314433 in words is "eleven billion, four hundred twelve million, three hundred fourteen thousand, four hundred thirty-three".