Base | Representation |
---|---|
bin | 10000100110110110110… |
… | …011101101011001000001 |
3 | 11001002201111212120102012 |
4 | 100212312303231121001 |
5 | 122144221213421032 |
6 | 2232135251102305 |
7 | 145310553231446 |
oct | 20466663553101 |
9 | 4032644776365 |
10 | 1141233342017 |
11 | 3aaaa351915a |
12 | 1652188a1995 |
13 | 838055271c2 |
14 | 3d3437a39cd |
15 | 1ea458ac6b2 |
hex | 109b6ced641 |
1141233342017 has 2 divisors, whose sum is σ = 1141233342018. Its totient is φ = 1141233342016.
The previous prime is 1141233342013. The next prime is 1141233342019. The reversal of 1141233342017 is 7102433321411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 884307021376 + 256926320641 = 940376^2 + 506879^2 .
It is a cyclic number.
It is not a de Polignac number, because 1141233342017 - 22 = 1141233342013 is a prime.
Together with 1141233342019, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1141233342013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570616671008 + 570616671009.
It is an arithmetic number, because the mean of its divisors is an integer number (570616671009).
Almost surely, 21141233342017 is an apocalyptic number.
It is an amenable number.
1141233342017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141233342017 is an equidigital number, since it uses as much as digits as its factorization.
1141233342017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 32.
Adding to 1141233342017 its reverse (7102433321411), we get a palindrome (8243666663428).
The spelling of 1141233342017 in words is "one trillion, one hundred forty-one billion, two hundred thirty-three million, three hundred forty-two thousand, seventeen".
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