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1141233342019 is a prime number
BaseRepresentation
bin10000100110110110110…
…011101101011001000011
311001002201111212120102021
4100212312303231121003
5122144221213421034
62232135251102311
7145310553231451
oct20466663553103
94032644776367
101141233342019
113aaaa3519161
121652188a1997
13838055271c4
143d3437a39d1
151ea458ac6b4
hex109b6ced643

1141233342019 has 2 divisors, whose sum is σ = 1141233342020. Its totient is φ = 1141233342018.

The previous prime is 1141233342017. The next prime is 1141233342047. The reversal of 1141233342019 is 9102433321411.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1141233342019 - 21 = 1141233342017 is a prime.

It is a super-2 number, since 2×11412333420192 (a number of 25 digits) contains 22 as substring.

Together with 1141233342017, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1141233342013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570616671009 + 570616671010.

It is an arithmetic number, because the mean of its divisors is an integer number (570616671010).

Almost surely, 21141233342019 is an apocalyptic number.

1141233342019 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141233342019 is an equidigital number, since it uses as much as digits as its factorization.

1141233342019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 34.

The spelling of 1141233342019 in words is "one trillion, one hundred forty-one billion, two hundred thirty-three million, three hundred forty-two thousand, nineteen".